35x^2-20=-3x

Solution for 35x^2-20=-3x equation:

35x^2-20=-3x

We move all terms to the left:

35x^2-20-(-3x)=0

We get rid of parentheses

35x^2+3x-20=0

a = 35; b = 3; c = -20;
Δ = b2-4ac
Δ = 32-4·35·(-20)
Δ = 2809
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2809}=53$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-53}{2*35}=\frac{-56}{70}
=-4/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+53}{2*35}=\frac{50}{70}
=5/7
$